Some input on pics

[Gearo]

TweetHi there,

I'm attaching pictures of friends who's like to have some feedback from you guys ! For the sake of simplicity, we'll call them Mr A, Mr B and Mr C (not Mr O ). As you'll notice they're in different development stage !

Mr A :

[Gearo]

TweetMr A (2nd) :

[Gearo]

TweetMr A (3rd) :

[Gearo]

TweetMr B now (1st) :

[Gearo]

TweetMr B (2nd) :

[Gearo]

TweetMr B (3rd) :

[Gearo]

TweetMr C (1st) :

[Gearo]

TweetMr C (2nd) :

[Gearo]

TweetMr C (3rd) :

[Solo]

TweetIf Mr. A and Mr. B walked 20 paces north and then Mr. B walked 10 paces south while Mr. C traveled 40 paces to the east. What is the total distance traveled if Mr. B wants to go stand next to Mr. C?

[LOCO]

Tweetwhat's a pace?

[Solo]

Tweeta step.

[Luftdude]

TweetYep, MR. C needs to work out more

LD

[Chimp]

TweetSorry GirlPatriot, but the correct answer is 41.2310562562 (rounded to ten decimal places).

Assume Mr. A, Mr. B and Mr. C all start at the same point. Mr. B moves twenty paces forward then 10 paces back. So Mr. B ends up ten paces north. Mr. C moves 40 paces east. The end result forms a right triangle. The short leg is 10 paces and the long leg is 40 paces and the hypotenuse would be the shortest path between them. Using Pythagorean theorem the sum of the squares of the two sides is equal to the sum of the hypotenuse. Therefore (10^2)+(40^2)=H^2 or 100+1600=H^2 which leads to 1700=H^2 or H=41.2310562562.

GirlPatriot your answer would be correct if Mr. B remained at 20 paces north.

I had to respond to this, it's the engineering geek coming out in me!

[Gearo]

TweetThanks guys, I'm really impressed by the engineering skills some of you have
But, beside Crank, nobody gave me real feedback, while I'm sure that there's a lot to say , No ?

Thank you all